Solution to

Work the following problems. Be sure to place the decimal point

Frame 3-16.

correctly in the product.

15.15207 (the multiplicand

NOTE: If there are not enough digits in the product, put zeros to the left

has 3 decimal places and

of the product until you have enough digits to place the decimal.

the multiplier has 2

Normally, you will also put another zero to the left of the decimal to

decimal places.

indicate that there are no whole numbers.

3 + 2 = 5, so the product

must have five decimal

places to the right of the

a. 0.0035

b. 22.222

c. 0.001

decimal point)

x 3.28

x 0.11

x 0.1

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Solution to

Frame 3-17.

that the divisor must be "changed" into a whole number before division is

started. This is done by moving the decimal point in the divisor all the

a. 0.0035 (4 places)

way to the right (that is, make the divisor a whole number).

x 3.28 (2 places)

0.011480 (6 places)

For example: 0.25 /

becomes 25./

by moving the decimal two

places to the right. In reality, you have just multiplied the divisor by 100.

(Note: When an answer

In order to offset this change, you must multiply the dividend by 100 also.

has a zero in the last

To do this, move the decimal in the dividend the SAME NUMBER of

decimal place, the zero is

places to the right. Add zeros to the dividend as needed.

often dropped -- 0.01148)

For example: 0.25 / 1.25 becomes 25./ 125.

b. 22.222 (3 places)

x 0.11 (2 places)

If you prefer, think of the problem as a fraction in which the denominator

2.44442 (5 places)

must be changed to a whole number.

c. 0.001

(3 places)

For example:

1.25

100

125

x 0.1

(1 place)

X

=

0.25

100

25

0.0001

(4 places)

Rewrite the following problems to remove the decimal in the divisor.

3.3 / 0.066

0.0033 / 66

0.000033 / 0.0066

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MD0900

3-9

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