Solution to

Frame 2-25.

"reduced." That is, you will want to use the name (form) of the fraction

No problem was given in

that has the smallest denominator possible that will still allow both the

Frame 2-25

numerator and denominator to remain whole numbers. The fraction is

then "reduced to its lowest form."

Below are three fractions, each in different forms. Circle the reduced

form of each fraction.

3

1

4

1/2 ;

2

1

54

;

2.5

10

5

=

=

=

=

=

=

=

6

2

8

1

3

1.5

81

4

16

8

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Solution to

Frame 2-26.

To reduce a fraction, find the largest whole number that can be divided

into both the numerator and denominator evenly (no remainders). Then

1

2

5

divide both the numerator and denominator by that number.

2

3

8

When reducing a fraction you must divide both the

and the

Remember, both the

numerator and the

by the same number.

denominator must be

whole numbers (not

fractions or decimals).

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MD0900

2-11

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