FRAME 2-26.
Solution to
Frame 2-25.
REDUCING FRACTIONS. Usually, you will want your answers
"reduced." That is, you will want to use the name (form) of the fraction
No problem was given in
that has the smallest denominator possible that will still allow both the
Frame 2-25
numerator and denominator to remain whole numbers. The fraction is
then "reduced to its lowest form."
Below are three fractions, each in different forms. Circle the reduced
form of each fraction.
3
1
4
1/2 ;
2
1
54
;
2.5
10
5
=
=
=
=
=
=
=
6
2
8
1
3
1.5
81
4
16
8
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FRAME 2-27.
Solution to
Frame 2-26.
To reduce a fraction, find the largest whole number that can be divided
into both the numerator and denominator evenly (no remainders). Then
1
2
5
divide both the numerator and denominator by that number.
2
3
8
When reducing a fraction you must divide both the
and the
Remember, both the
numerator and the
by the same number.
denominator must be
whole numbers (not
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MD0900
2-11