e. EXAMPLE #4. A 35-year-old female has been burned by a chemical and has
second- and third-degree burns over 25 percent of her body. She weighs 115 pounds.
24 hours. Calculate the fluid needed for the 2nd and the 3rd
8-hour periods.
SOLUTION:
STEP 1. TBSA burned is 25 percent.
STEP 2. 115 lbs divided by 2.2 = 52 kg (weight in kg)
STEP 3. Calculate by formula:
4cc X TBSA X weight in kgs = fluid
4
X 25
X 52
= 5,200 cc (in first
24 hours.
STEP 4. Calculate fluid replacement for second and third
8-hr periods.
Second 8 hrs. Fourth of first 24-hr fluid replacement
5,200 divided by 4 = 1.300 cc (fluid replacement in
second 8 hours)
Third 8 hrs. Fourth of first 24-hr fluid replacement
5,200 divided by 4 = 1.300 cc (fluid replacement in
third 8 hours)
MD0576
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