Convert 6.0 Eq/L Ca3(PO4)2 to mol/L.
6.0 Eq
1 mol
------ X -------- = 1.0 mol/L
L
6 Eq
Convert 31 g/dL Ca3(PO4)2 to mol/L.
Calculate the GMW of Ca3(PO4)2.
Ca3(PO4)2
Ca
40.1 X 3 = 120.3
P
31.0 X 2 =
62.0
O
16.0 X 8 = + 128.0
310.3 g/mol
Use the appropriate factors to determine the mol/L concentration.
31 g 1 mol
10 dL
----X -------- X ------ = 1.0 mol/L
dL
310.3 g
1L
Determine the total volume.
1.0 mol/L
5.0 mL
2.0 mol/L 8.0 mL
1.0 mol/L + 3.0 mL
16.0 mL
Substitute the given information and solve for the unknown quantity.
C1V1 = C2V2 + C3V3 . . . + CnVn
(C1)(16.0 mL) = (1.0 mol/L)(5.0 mL)+(2.0 mol/L)(8.0 mL)+(1.0 mol/L)(3.0 mL)
(1.0 mol/L)(5.0 mL)+(2.0 mol/L)(8.0 mL)+(1.0 mol/L)(3.0 mL)
C1 = --------------------------------------------------------
6 mL
C1 = 1.5 mol/L
MD0837
6-10