Solution:

(a)

The total amount of the preparation is 60 milliliters.

(b)

One percent of the total amount is 0.6.

(c)

0.6 X 1/2 =

0.6 = 0.3 grams of holocaine HCL needed.

2

(d)

0.6 X 1/3 =

0.6 = 0.2 grams of chlorobutanol needed.

3

d.

Practical Exercise. Work the following exercises and check your answers.

(1) How many grams of boric acid will be needed to make 500 g of a 4%

(w/w) ointment?

(2) How many grams of strong silver protein (SSP) are required to make 250

ml of a 0.25% (w/v) solution?

(3) How many grams of boric acid are there in 1 gallon of a 4% (w/v) boric

acid solution?

(4) If 5 g of a chemical is dissolved in enough water to make the preparation

measure one liter, what is the percentage strength of the solution?

(5) How many milliliters of a 0.02% W/V solution can be made from 2.5 g of

a chemical?

MD0802

2-17

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