SOLUTIONS TO EXERCISE, LESSON 2
1.
c
(para 2-1)
2.
b, c (para 2-2)
3.
hypochorous acid, free hypochlorite ion. (para 2-3)
4.
c
para 2-3a)
5.
100 mg
5 ppm = 5 mg/I
5 mg = X mg
1
20
X = 5 x 20 = 100 mg (para 2-10c)
1
6.
a
(para 2-3b, c)
7.
4 oz.
3,000 gal x 8.34 lb/gal = 25,020 lb
10___ =
X lb____
1,000,000
25,020 lb
X = 10 x 25,020 =
250,200 = 0.25 lb (4 oz) (para 2-12c)
1,000,000
1,000,000
8.
5.7 oz.
70 percent = 0.7
0.7X = 4 oz
X = _4_ = 5.7 oz (para 2-12c)
0.7
MD0160
2-28