Thus, on the left side of the equation, we need twice as much

_________________. On the right side of the equation, we need twice as much

_____________. In order to satisfy this requirement, the equation becomes

__________________.

On each side of the equation, we now have (one) (two) calcium atoms(s), (one)

(two) hydroxide radical(s), (one) (two) hydrogen atoms, and (one) (two) (three)

nitrate radicals. Since we now have an equal number of each type of atom and

radical on both sides of the equation, we can say that the equation is

__________________.

4.

Sulfuric acid and ferric hydroxide react to produce ferric sulfate and water. The

equation without balancing is:

_________+________ ------> _________+________

Now, list the reactants and the products as in the previous exercise.

REACTANTS

PRODUCTS

_______ H

_______ H

_______ SO4

_______SO4

_______ Fe

_______ Fe

_______ OH

_______ OH

Now, balance the equation. (Before looking at the answer, be sure you have the

same number of each type of atom or radical on both sides of the equation.)

__H2SO4 + __ Fe (OH)3 ----> __Fe2(SO4)3 + __ HOH

5.

Iron metal and sulfur react to yield ferrous sulfide. The balanced equation for this

reaction is ______________________________.

6. Sodium carbonate and hydrochloric acid react to yield sodium chloride, water, and

carbon dioxide gas. Use a piece of scratch paper to write the balanced equation.

The balanced equation is ________________________.

Did you forget the arrow after CO2? The arrow means that CO2 is given off as a

_______________.

MD0803

2-28

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